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The mutual inductance between a primary and secondary circuit is `0.5H`. The resistance of the primary and the secondary circuits are `20 ohms` and `5ohms` respectvely. To genrate a current of `0.4A` in the secondary,current in the primary must be changed at the rate ofA. `4.0 A//s`B. `16.0 A//s`C. `1.6 A//s`D. `8.0 A//s` |
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Answer» Correct Answer - A `e_(e)=M(di_(1))/(dt)=0.4xx5=0.5xx(di_(1))/(dt)` `implies(di_(1))/(dt)=4 A//sec`. |
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