The motion of a particle executing simple harmonic motion is described by the displacement function, x(t)=Acos(omegat+phi). If the initial (t = 0) position of the particle is 1 cm and its initial velocity is omega cm/s, what are its amplitude and initial phase angle ? The angular frequency of the particle is pi s^(-1). If instead of the cosine function, we choose the sine function to describe the SHM : x = B sin (omegat + alpha), what are the amplitude and initial phase of the particle with the above initial conditions.

The motion of a particle executing simple harmonic motion is described

1.	The motion of a particle executing simple harmonic motion is described by the displacement function, x(t)=Acos(omegat+phi). If the initial (t = 0) position of the particle is 1 cm and its initial velocity is omega cm/s, what are its amplitude and initial phase angle ? The angular frequency of the particle is pi s^(-1). If instead of the cosine function, we choose the sine function to describe the SHM : x = B sin (omegat + alpha), what are the amplitude and initial phase of the particle with the above initial conditions.
Answer» SOLUTION :`A=sqrt2cm,phi=7pi//4,B=sqrt2cm,a=pi//4`