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The motion of a particle along a straight line is described by the equation x = 4 – 12t + 3t3, where x is in metre and t is in second. Acceleration of the particle at t = 2 second will be |
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Answer» hat, x = 4 - 12T + 3t³ where x is in METRE and t is in second. We know that,v = dx/dt and a = dv/dtSo, v = d(4 - 12t + 3t³)/dtv = -12 + 3t²Also, a = d(-12 + 3t²)/dta = 3tWe have to FIND the ACCELERATION of the particle at the time (t) = 2 secondSimply, substitute value of t = 2 sec in a = 3t. To find the value of acceleration.→ a = 3(2)→ a = 6Therefore, of the particle at t = 2 second is 6 m/s². |
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