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The motion of a particle along a straight line is described by equation : `x = 8 + 12 t - t^3` where `x` is in metre and `t` in second. The retardation of the particle when its velocity becomes zero is.A. `6 ms^(-2)`B. `12 ms^(-2)`C. `24 ms^(-2)`D. zero |
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Answer» Correct Answer - B `x=8+12t-t^(3)` `v=(dx)/(dt)=12-3t^(2)` `a=(dv)/(dt)=-6t` putting v=0 `3t^(2)=12` t=2 sec `therefore a= -6xx2=-12 ms^(-2)` `therefore` retardation `=12 ms^(-2)` |
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