The momentum of the body is doubled, what % does its K.E. change ?

1.	The momentum of the body is doubled, what % does its K.E. change ?
Answer» <P> Solution :`K.E.=p^(2)/(2m)"when p is doubled K.E.as K.E.becomes 4 TIMES"` `THEREFORE%"INCREASE in K.E."=(triangleK.E.)/(K.E)xx100(4K.E-K.E.)/(K.E)XX100=3XX100=300%`

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