1.

The moment of inertia of a uniform circular disc of mass M and radius R about any of its diameter is (1)/(4)MR^(2). What is the moment of inertia of the disc about an axis passing through its centre and normal to the disc?

Answer»

`MR^(2)`
`2MR^(2)`
`(3)/(2)MR^(2)`
`(1)/(2)MR^(2)`

Solution :By THEOREM of `_|_` AXIS
`I_(Z Z.)=I_(AB)+I_(CD)=(1)/(4)MR^(2)+(1)/(4)MR^(2)`

`I_(Z Z.)=(1)/(2)MR^(2)`


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