1.

The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its midpoint and perpendicular to its length is I_(0). Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is .............

Answer»

`I_(0)+(ML^(2))/(2)`
`I_(0)+(ML^(2))/(4)`
`I_(0)+2ML^(2)`
`I_(0)+ML^(2)`

Solution :
The MOMENT of inertia about the MIDDLE axis is `I_(0)`, Now ACCORDING to parallel axis
`I=I_(0)+Md^(2)`
putting `d=(L)/(2)`
`I=I_(0)+M((L)/(2))^(2)`
`therefore I=I_(0)+(ML^(2))/(4)`


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