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The moment of inertia of a squaer lamin about the perpendicluar axis though its centre of mass is ` 20 kg- m^(2)` . Then its moment of inertia about an axis toching its side and in the plane of the lamina will be : -A. `10 kg - m^(2)`B. `30 kg- m^(2)`C. `40 k g- m^(2)`D. `25 kg m^(2)` |
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Answer» Correct Answer - C `(Ml^2)/(6)=20 rArr Ml^2 = 120 ` `I= (Ml^2)/(12)+(Ml^2)/(4)=(Ml^2)/(3)=40 kg m^2 ` |
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