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The moment of inertia of a disc about an axis passing through its centre and normal to its plane is I. The disc is now folded along a diameter such that the two halves are mutually perpendicular. Its moment of inertia about this diameter will now be (a) I (b) I/√2 (c) I/2 (d) I/4 |
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Answer» Correct Answer is: (c) I/2 I = 1/2 mR2. For a diameter, moment of inertia = 1/2.
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