The moment of inertia of a cube of mass m and side a about one of its

1.	The moment of inertia of a cube of mass m and side a about one of its edges is equal to
Answer» `(2)/(3) ma^(2)` `(4)/(3)ma^(2)` `3MA^(2)` `(8)/(3)ma^(2)` Solution :From theorem of perpendicular axes, we have `I=I_(C)+m((a)/(sqrt(2)))^(2)=((ma^(2))/(12)+(ma^(2))/(12))+(ma^(2))/(2)=(2)/(3)ma^(2)`.

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