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the mole percent of oxygen present in gaseous mixture containing 10 g of nitrogen and 8 g of o oxygen is? |
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Answer» no. of MOLES of N =10/14=0.714 no. of moles of O =8/16=0.5 mole % of OXYGEN = 0.5/(0.714+0.5)×100 = 0.4117×100 = 41.17%
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