1.

the mole percent of oxygen present in gaseous mixture containing 10 g of nitrogen and 8 g of o oxygen is?

Answer»

no. of MOLES of N =10/14=0.714

no. of moles of O =8/16=0.5


mole % of OXYGEN = 0.5/(0.714+0.5)×100

= 0.4117×100

= 41.17%



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