The molarity of the KOH solution which is 2.8% (mass/volume) solution

1.	The molarity of the KOH solution which is 2.8% (mass/volume) solution is :(A) M/10 (B) M/2 (C) M/5 (D) 1 M
Answer» 2.8%m/v means 100ml of SOLUTION has 2.8g of KOH Volume of solution=100ml=0.1L MASS of KOH= 2.8g MOLAR mass of KOH= 56 Moles(KOH) = Mass /Molar mass Moles(KOH)=0.05 Molarity = moles(KOH)/Volume of solution(L) Molarity=0.05/0.1 Molarity=0.5M I HOPE this HELPS ( ╹▽╹ )

The molarity of the KOH solution which is 2.8% (mass/volume) solution is :(A) M/10 (B) M/2 (C) M/5 (D) 1 M

Answer»

2.8%m/v means 100ml of SOLUTION has 2.8g of KOH

Volume of solution=100ml=0.1L

MASS of KOH= 2.8g

MOLAR mass of KOH= 56

Moles(KOH) = Mass /Molar mass

Moles(KOH)=0.05

Molarity = moles(KOH)/Volume of

solution(L)

Molarity=0.05/0.1

Molarity=0.5M

I HOPE this HELPS ( ╹▽╹ )