The molarity of hcl solution by dissolving 4.6g of it in 250 ml water

1.	The molarity of hcl solution by dissolving 4.6g of it in 250 ml water is
Answer» $\mathfrak{\large{\underline{\underline{Answer:-}}}}$ $\mathfrak{\large{\underline{\underline{Given :-}}}}$ MASS of HCL is = 4.6 g Volume of water = 250 ml $\mathfrak{\large{\underline{\underline{Solution:-}}}}$ Molarity is DEFINED as number of moles present per l of solution. $\bold{No . of moles of HCl =\frac{given \: mass}{formula \: mass} }$ No. of moles of HCl = $\bold{ \frac{4.6}{36.5} }$ No. of moles of HCl = 0.12 mol Now, we can use formula of molarity :- ★ $\boxed{\sf{ Molarity = \frac{no. \: of \: moles \: of \: HCl}{volume \:o f\:solution \: } }}$ $\implies$ Molarity = $\bold{ \frac{0.12}{250} \times 1000}$ $\implies$ Molarity = $\bold{0.12 × 4}$ $\implies$ Molarity = $\bold{0.48}$ hence, the molarity of 250 ml of HCl is 0.48M.