1.

The molarity of 250 ml of Na2 CO3 solution is 0.5 M. Find the mass of Na2 CO3 .

Answer»

M = \(\frac{n}{v}\); M = 0.5,V = 250 ml = 0.25 L

0.5 = \(\frac{n}{0.25}\) ; n = 0.5 x 0.25 = 0.125

GMM of Na2CO3 = 23 x 2 + 12 x 1 + 16 x 3 = 106 g

∴ Mass of Na2 CO3 in the solution of 250 ML

with 0.5 Na2CO3 = 0.125 x 106 = 13.25g



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