The molar solubility of Zn(OH)2 in 0.1 M NaOH solution is x×10−18M. – InterviewSolution

1.	The molar solubility of Zn(OH)2 in 0.1 M NaOH solution is x×10−18M. The value of x is .......(Nearest integer)(Given: The solubility product of Zn(OH)2 is 2×10−20)
Answer» The molar solubility of $Z n {(O H)}_{2}$ in 0.1 M NaOH solution is $x \times 10^{- 18} M$ . The value of x is .......(Nearest integer) (Given: The solubility product of $Z n (O H)_{2} is 2 \times 10^{- 20}$ )

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