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The molar conductivity of 0.025 mol L−1 methanoic acid is 46.1 S cm2 mol−1.Calculate its degree of dissociation and dissociation constant.Given λ °(H+)= 349.6 S cm2 mol−1 and λ°(HCOO−) = 54.6 S cm2 mol |
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Answer» The molar conductivity of 0.025 mol L−1 methanoic acid is 46.1 S cm2 mol−1. Calculate its degree of dissociation and dissociation constant. = 349.6 S cm2 mol−1 and λ |
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