1.

The molar conductivity of 0.025 mol L−1 methanoic acid is 46.1 S cm2 mol−1.Calculate its degree of dissociation and dissociation constant.Given λ °(H+)= 349.6 S cm2 mol−1 and λ°(HCOO−) = 54.6 S cm2 mol

Answer»

The molar conductivity of 0.025 mol L−1 methanoic acid is


46.1 S cm2 mol−1.


Calculate its degree of dissociation and dissociation constant.
Given λ °(H+)


= 349.6 S cm2 mol−1 and λ
°(HCOO−) = 54.6 S cm2 mol



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