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The molar conductance of ammonium hydroxide solution of concentration 0.1 M, 0.01M and 0.001 M are 3.6, 11.3 and `34.0 ohm^(-1)cm^(-2)mol^(-1)` respectively. Calculate the degree of dissociation of `NH_(4)OH` at these concentrations. Molar conductance at infinite dilution for `Nh_(4)OH` is 271.1 ohm^(-1)cm^(-1)mol^(-1)`. |
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Answer» Correct Answer - 0.0133, 0.0417, 0.1254 At 0.1 M concentraton , `" "(alpha)=(Lambda_(m)^(C ))/(Lambda_(m)^(oo))=((3.6" ohm"^(-1)cm^(2)mol^(-1)))/((271.1" ohm"^(-1)cm^(2)mol^(-1)))=0.0133` At 0.01 M concentration , `" "(alpha)=(Lambda_(m)^(C ))/(Lambda_(m)^(oo))=((11.3" ohm"^(-1)cm^(2)mol^(-1)))/((271.1" ohm"^(-1)cm^(2)mol^(-1)))=0.0417` At 0.001 M concentration , `" "(alpha)=(Lambda_(m)^(C ))/(Lambda_(m)^(oo))=((34.0" ohm"^(-1)cm^(2)mol^(-1)))/((271.1" ohm"^(-1)cm^(2)mol^(-1)))=0.1254`. |
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