1.

The molality of `1 L` solution with `x% H_(2)SO_(4)` is equal to 9. The weight of the solvent present in the solution is `910 g`. The value of `x` is:A. 90B. 80.3C. 40.13D. 9

Answer» Correct Answer - B
Molality `= (1000 xx "Weight of solute")/(Mw xx "Weight of solven")`
`9 = (1000 xx W)/(98 xx 910)`
`W = 802.6 gL^(-1)`
`= 80.26 g` per `100 mL`


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