1.

The minimum value of f(x)=2x^2+3x+1 is

Answer»

ANSWER:

2 {x}^{2}  + 3x + 1 = 0

= 2 {x}^{2}  + (2 + 1)x + 1 = 0

= 2 {x}^{2}  + 2x + x + 1 = 0

= 2x( x + 1) + (x + 1) = 0

= (2x + 1)(x + 1) = 0

= x =  - 1 \: and \: x =  \frac{ - 1}{2}

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