1.

The minimum quantity in grams of H2S needed to precipitate 63.5 g of Cu2+ ion will be: (molar mass of Cu=63.5 g/mol) Cu2++H2S→CuS+2H+

Answer»

The minimum quantity in grams of H2S needed to precipitate 63.5 g of Cu2+ ion will be:
(molar mass of Cu=63.5 g/mol)

Cu2++H2SCuS+2H+



Discussion

No Comment Found