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The minimum energy required to launch an m kg satellite from the earth’s surface in a circular orbit at an altitude of 2R, where R is the radius of earth, will be? i want complet explanation |
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Answer» n :Since gravitation force provides the necessary centripetal force;∴ The velocity required by an object at distance 2R from centre is found out by putting in 2R in place of R in the above formula.Now the total ENERGY of an object at a height is given by :E= P.E + K.ENow putting in values of v and r as 2R, we get final energy of an orbiting body as :Initial energy of satellite at earth's SURFACE is given by [where v' is the speed provided so as to reach orbit]Now equating due to conservation of energySo the minimum kinetic energy required is : And minimum total energy(with PE component)is: [as obtained for ]Hope this ANSWER helped you :) |
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