The measure of angles of a hexagon are x°, (x-5)°, (x-5)°, (2x-5)�

1.	The measure of angles of a hexagon are x°, (x-5)°, (x-5)°, (2x-5)°, (2x-5)°, (2x+20)°. Find value of x.
Answer» By using the formula, The sum of interior angles of a polygon = (n – 2) × 180°, (where n = number of sides of polygon.) We know, a hexagon has 6 sides. So, The sum of interior angles of a hexagon = (6 – 2) × 180° = 4 × 180° = 720° x°+ (x-5)°+ (x-5)°+ (2x-5)°+ (2x-5)°+ (2x+20)° = 720° x°+ x°- 5°+ x° – 5°+ 2x° – 5°+ 2x° – 5°+ 2x° + 20° = 720° 9x° = 720° x = 720°/9 = 80° ∴ Value of x is 80°^.

The measure of angles of a hexagon are x°, (x-5)°, (x-5)°, (2x-5)°, (2x-5)°, (2x+20)°. Find value of x.

Answer»

By using the formula,

The sum of interior angles of a polygon = (n – 2) × 180°, (where n = number of sides of polygon.)

We know, a hexagon has 6 sides. So,

The sum of interior angles of a hexagon = (6 – 2) × 180° = 4 × 180° = 720°

x°+ (x-5)°+ (x-5)°+ (2x-5)°+ (2x-5)°+ (2x+20)° = 720°

x°+ x°- 5°+ x° – 5°+ 2x° – 5°+ 2x° – 5°+ 2x° + 20° = 720°

9x° = 720°

x = 720°/9

= 80°

∴ Value of x is 80°^.