The mean and variance of a binomial distribution are 12 and 3 respec – InterviewSolution

1.

The mean and variance of a binomial distribution are 12 and 3 respectively. Find the probability distribution.

Answer»

For binomial distribution,

mean = nP = 12 and variance = npq = 3

12q = 3

q = 1/4

∴ P = 1 - q = 1 - (1/4) = 3/4

and n.p = 12

n.(3/4) = 12

n = 16

∴ Binomial distribution is

(P + q)ⁿ= ((3/4) + (1/4))¹⁶

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