1.

The maximum speed of particle performing S.H.M. is 6.28 cm/s , if the length of its path is 8cm,then its period is...​

Answer»

ong>Answer:

HOPE this will help you

Please mark me as brainleast

Explanation:

v= 6.28

l of path = 8 CM

that means Amplitude A = 4 cm

v=omega*A

omega= v/A =6.28/4

time PERIOD= 2π/(omega)

= 6.28/(omega) =4 s



Discussion

No Comment Found

Related InterviewSolutions