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The maximum speed of particle performing S.H.M. is 6.28 cm/s , if the length of its path is 8cm,then its period is... |
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Answer» ong>Answer: HOPE this will help you Please mark me as brainleast Explanation: v= 6.28
l of path = 8 CM
that means Amplitude A = 4 cm
v=omega*A
omega= v/A =6.28/4
time PERIOD= 2π/(omega)
= 6.28/(omega) =4 s
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