The maximum resul†an t of 2 vector A and B(A≥ B) is n times their least resul†an t. If θ be the angle between the two vectors and their resul†an t is half of the sum of vector. Then show that Cosθ= -n^2+2/2(n^2-1

The maximum resul†an t of 2 vector A and B(A≥ B) is n times their

1.	The maximum resul†an t of 2 vector A and B(A≥ B) is n times their least resul†an t. If θ be the angle between the two vectors and their resul†an t is half of the sum of vector. Then show that Cosθ= -n^2+2/2(n^2-1
Answer» The maximum resul†an t of 2 vector A and B(A≥ B) is n times their least resul†an t. If θ be the angle between the two vectors and their resul†an t is half of the sum of vector. Then show that Cosθ= -n^2+2/2(n^2-1