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The maximum possible error in the difference of two quantities is …… (a) Z = A + B (b)∆Z = ∆A - ∆B (c) \(\frac{∆Z}{Z}\) = \(\frac{∆A}{A}\) + \(\frac{∆B}{B}\)(d)\(\frac{∆Z}{Z}\) = \(\frac{∆A∆B}{AB}\) |
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Answer» Correct answer is (c) \(\frac{∆Z}{Z}\) = \(\frac{∆A}{A}\) + \(\frac{∆B}{B}\) |
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