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The maximum `pH` of a solution which is having `0.10M` in `Mg^(2+)` and from which `Mg(OH)_(2)` is not precipated is: (Given `K_(sp)Mg)(OH)_(2)=4xx10^(11)M^(3)){log2=0.30}`A. `10.3`B. `3.7`C. `7.5`D. `9.3` |
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Answer» Correct Answer - D The concentration of `OH^(-)` required to precipitate `Mg(OH)_(2)` is `[OH]=((K_(sp))/([Mg^(2+)]))^(1//2)=((4xx10^(-11)M^(3))/(0.10M))^(1//2)` `pOH=log(2xx10^(5))=4.7` and `pH=4.7=9.3` |
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