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The maximum oxidation state shown by `V(Z=23),Cr(Z=24),Co(Z=27),Sc(Z=21)`, are respectivelyA. `+5, +6, +3,+3`B. `+3,+4,+5,+2`C. `+5,+3,+2,+1`D. `+4` in each case. |
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Answer» Correct Answer - A (A)Electron configuration of V is [Ar] `3d^3 4s^2` and thus maximum 5 electrons participate in bonding. (B)Electron configuration of Cr is [Ar] `3d^5 4s^1` and thus maximum 6 electrons participate in bonding. ( C)Electron configuration of Co is [Ar] `3d^7 4s^2`.In octahedral splitting in presence of ligands , half filled `t_(2g)^6` has higher CFSE and thus +3 oxidation state is most stable. (D)Electron configuration of Sc is [Ar] `3d^1 4s^2` and thus maximum 3 electrons participate in bonding. |
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