The masses of the three wires of copper are in the ratio `5:3:1` and their lengths are in the ratio `1:3:5`. The ratio of their electrical resistances isA. `15:1:125`B. `1:125:15`C. `125:1:15`D. `125:15:1`

The masses of the three wires of copper are in the ratio `5:3:1` and t

1.	The masses of the three wires of copper are in the ratio `5:3:1` and their lengths are in the ratio `1:3:5`. The ratio of their electrical resistances isA. `15:1:125`B. `1:125:15`C. `125:1:15`D. `125:15:1`
Answer» Correct Answer - D Resistance in terms of length and mass is given by, `R prop (l^(2))/(m)` `:.R_(1):R_(2):R_(3)=(l_(1)^(2))/(m_(1)):(l_(2)^(2))/(m_(2)):(l_(3)^(2))/(m_(3))` `R_(1):R_(2):R_(3)=(25l_(1)^(2))/(m_(1)):(9l_(1)^(2))/(3m_(1)):(l_(1)^(2))/(5m_(1))` `=25:3:1/5` `=125:15:1`.

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The masses of the three wires of copper are in the ratio `5:3:1` and their lengths are in the ratio `1:3:5`. The ratio of their electrical resistances isA. `15:1:125`B. `1:125:15`C. `125:1:15`D. `125:15:1`

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