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The mass of water 300g the temperature 30 ° C is heated so that it becomes a whole steam. Caloric water type 1000J / kg ° C, steam heat 227000J / ° C. What is the amount of heat needed? |
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Answer» Known: m = 300 gr = 0.3 kg To = 30 C c water = 1000 J / KgC U = 227,000 J / Kg Asked: Q? Answered: Q1 = m x c x (T-To) = 0.3 x 1000 x (100-30) = 0.3 x 1000 x 70 = 21,000 J Q2 = m x U = 0.3 x 227,000 = 68,100 J So the required heat = 21000 + 68100 = 89,100 J
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