ss of Jupiter, M = 1.9 × 10²⁷ kg RADIUS of Jupiter, R = 71 × 10⁶ m Universal Gravitational constant, G = 6.67 × 10⁻¹¹ Nm²kg⁻² Mass of person on Jupiter's surface, m = 800 kg To findAcceleration due to gravity on jupiter's surface, g =? Weight of person with 800 kg mass, W =?Formulae requiredFormula for acceleration due to gravity         g = GM / R²Formula for weight of body         W = mg [ Where g is acceleration due to gravity, G is universal gravitational constant, M is mass of specific celestial body, R is the DISTANCE between centre and surface of celestial body, W is the weight of body of mass m on Jupiter's surface] SolutionCalculating the acceleration due to gravity of jupiter USING formula → g = GM / R² → g = (6.67 × 10⁻¹¹ Nm²kg⁻²) (1.9 × 10²⁷ kg) / (71 × 10⁶ m)²→ g = 0.00251 × 10⁴ → g = 25.1 m/s²Now,Calculating the weight of person with mass 800 kg → W = mg→ W = 800 × 25.1 → W = 20080 N Therefore,Acceleration due to gravity of jupiter is 25.1 m/s², andWeight of the person is be 20080 N.