1.

The mass of BaCO3 produced when excess of CO2 is bubbled through a solution of 0.205 mole Ba(OH)2 solution, is: (Take molar mass of Ba=137 g/mol) Ba(OH)2+CO2→BaCO3+H2O

Answer»

The mass of BaCO3 produced when excess of CO2 is bubbled through a solution of 0.205 mole Ba(OH)2 solution, is:
(Take molar mass of Ba=137 g/mol)

Ba(OH)2+CO2BaCO3+H2O



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