The mass of a square block is 750 g. If the base of length is 10 cm, f

1.	The mass of a square block is 750 g. If the base of length is 10 cm, find the average pressure exerted by the block on its base.
Answer» ⭐《ANSWER》 $\huge\mathfrak{\underline {\underline\pink {ANSWER}}}$ ↪Actually WELCOME to the concept of the FORCE AND PRESSURE ↪Basically here , we are DEALING with the Normal pressure exerted by a object ( square) on its RESPECTIVE base, ↪Since here , the Object dimension is a SQAURE , so we get as , 〽Pressure = Force / AREA , ↪Since here , the pressure is normal to base , also the force is normal to base , thus ↪Force = MG ( g = acceleration due to gravity = 10 m/s^2) ↪so we get as , ↪F = (0.75)(10) ↪F = 7.5 N ↪now the base area , will be as , ↪Area = (side)^2 ↪Area = (0.1)^2 m^2 ↪Area = 0.01 m^2 ↪so now here , ↪PRESSURE = 7.5/0.01 〽P = 750 pa ↪Since here , the SI UNIT of pressure is N/m^2 or Pascals or Pa ↪so we get as , ⭐PRESSURE ON THE BASE = 750 Pa

The mass of a square block is 750 g. If the base of length is 10 cm, find the average pressure exerted by the block on its base.

Answer»

⭐《ANSWER》

$\huge\mathfrak{\underline {\underline\pink {ANSWER}}}$

↪Actually WELCOME to the concept of the FORCE AND PRESSURE

↪Basically here , we are DEALING with the Normal pressure exerted by a object ( square) on its RESPECTIVE base,

↪Since here , the Object dimension is a SQAURE , so we get as ,

〽Pressure = Force / AREA ,

↪Since here , the pressure is normal to base , also the force is normal to base , thus

↪Force = MG ( g = acceleration due to gravity = 10 m/s^2)

↪so we get as ,

↪F = (0.75)(10)

↪F = 7.5 N

↪now the base area , will be as ,

↪Area = (side)^2

↪Area = (0.1)^2 m^2

↪Area = 0.01 m^2

↪so now here ,

↪PRESSURE = 7.5/0.01

〽P = 750 pa

↪Since here , the SI UNIT of pressure is N/m^2 or Pascals or Pa

↪so we get as ,

⭐PRESSURE ON THE BASE = 750 Pa

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