1.

The mass of a litre of gas is 1.562 g at 0^(0)C under a pressure of 76 cm of mercury. The temperature is increased to 250^(0)C and the pressure to 78 cm of mercury. What is the mass of one litre of the gas under new conditions ?

Answer»

Solution :`(P_(1))/(rho_(1)T_(1)) = (P_(2))/(rho_(2) T_(2))`
(or) `rho_(2) = (P_(2) T_(1)rho_(1))/(P_(1)T_(2)) = (78 xx 273 xx 1.562)/(76 xx 523) = 0.8366` g /LIT
`therefore` Mass of l Jitre of the GAS under new conditions is 0.8366 g.


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