1.

The mass of a body is 20.0 g and its volume is 10.0 cm^(3). If possible maximum errors in the measurement of mass of body and volume of body are 0.001 g and 0.01 cm^(3) respectively, then the maximum error in the value of density is

Answer»

` 0.001 g cm^( -3)`
` 0.010 g cm^( -3)`
` 0.10 g cm^( -3)`
NONE of these

Solution :Maximum error in measuring mass is 0.001g, and maximum error in measuring volume is `0.01 cm^(3)`
As density `RHO= (M)/(V)`
`:. (Deltarho)/(rho)= (DeltaM)/(M)+ (DeltaV)/(V)= (0.001)/(20.0)+ (0.01)/(10.0)= (5 XX 10^(-5))+ (1 xx 10^(-3))= 1.05 xx 10^(-3)`
or `Deltarho = (1.05 xx 10^(-3))xxrho= 1.05 xx 10^(-3) xx 10^(-3) xx (20.0)/(10.0)= 0.002gcm^(-3)`


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