1.

The magnitude of two vectors are 12 and 18 units and their resultant is 24 units find the angle between the two vectors

Answer»

24 =  \sqrt{ {12}^{2} +  {8}^{2} + 2 \times 12 \times 18  \cos( \theta )  }

sbs

576 =  {144 + 324 + 432 \cos( \theta ) }

576 - 468 = 432 \cos( \theta )

108 = 432 \cos( \theta )

\cos( \theta )  =  \frac{1}{4}

\theta  =  { \cos }^{ - 1}  (\frac{1}{4} )



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