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The magnifying power of an astronomical telescope in the normal adjustment position is 100. The distance between the objective and the eyepiece is 101 cm. Calculate the focal length of the objective and the eyepiece. |
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Answer» SOLUTION :Here, `|m| =f_(0)/f_(e) = 100rArr f_(0) = 100 f_(e)` and `f_(0) + f_(e) =101 cm` or `100f_(e) + f_(e) = 101 f_(e) = 101 cm` `RARR f_(e)= 1CM` and `f_(0) = 100 cm = 1 cm` |
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