1.

The magnifying power of a telescope with tube 60 cm is 5. What is the focal length of its eye piece ?(1) 30 cm(2) 40 cm(3) 20 cm(4) 10 cm

Answer»

Answer is (4) 10 cm

L = f0 + fe = 60 cm 

M = f0/fe = 5

f0 = 5fe

∴ 6fe = 60 cm

fe = 10 cm

Answer is (4) 10 cm

m = f0/fe

5 = f0/fe

f0 = 5fe

f0 + fe = 60 

6fe = 60 

fe = 10 



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