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The magnifying power of a telescope with tube 60 cm is 5. What is the focal length of its eye piece ?(1) 30 cm(2) 40 cm(3) 20 cm(4) 10 cm |
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Answer» Answer is (4) 10 cm L = f0 + fe = 60 cm M = f0/fe = 5 f0 = 5fe ∴ 6fe = 60 cm fe = 10 cm Answer is (4) 10 cm m = f0/fe 5 = f0/fe f0 = 5fe f0 + fe = 60 6fe = 60 fe = 10 |
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