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The magnetic flux through a coil is varying according to the relation `phi = (5 t^(3) + 4 t^(2) + 2t - 5)` Wb. Calculate the induced current through the coil at `t = 2` s if resistiance of coil is 5 ohm. |
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Answer» `phi = 5t^(3)+4t^(2)+2t-5` `|e| = (d phi)/(dt) = 15 t^(2)+8t+2` at `t = 2 sec, e = 78V` `i xx 5 = 15 xx 4+8xx2+2 rArr i = 15.6A` |
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