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The magnetic flux threading a coil changes from `12 xx 10^(-3)` Wb to `6 xx 10^(-3)` Wb in 0.01. Calculate the induced e.m.f. |
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Answer» Here, `phi_(1) = 12 xx 10^(-3) Wb, phi_(2) = 6 xx 10^(-3) Wb`, `dt = 0.1 s = 10^(2)s, e = ?` `e = (- d phi)/(dt) = (-(phi_(2) - phi_(1)))/(dt)` `= (-(6 xx 10^(-3) - 12 xx 10^(-3)))/(10^(2))` `e = 0.6` volt |
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