Saved Bookmarks
| 1. |
The magnetic flux of `phi` (in weber) in a closed circuit of resistance `3 ohm` varies with time `t ` (in second according to the equation `phi = 2 t^(2) - 10 t` at ` t = 0.25 s`? |
|
Answer» Correct Answer - 3 Here, `R = 3 Omega, phi = 2 t^(2) - 10 t +3, I = ?, t = 0.25 s` `e = - (d phi)/(dt) = - (d)/(dt) (2 t^(2) - 10 t + 3)` `e = - 4 t + 10` At `t = 0.25 s, e = - 4 xx 0.25 + 10 = 9` volt `I = (e)/(R ) = (9)/(3) = 3 A` |
|