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The magnetic field at the centre of a current carrying circular coil of radius 10 cm is 5√5 times the magnetic field at a point on its axis. The distance of the point from the centre of the coil is ( Kindly explain each step )(x² + R²) ^3/2 = 5√5 R³ specially this one

Answer» The magnetic field at the centre of a current carrying circular coil of radius 10 cm is 5√5 times the magnetic field at a point on its axis. The distance of the point from the centre of the coil is
( Kindly explain each step )
(x² + R²) ^3/2 = 5√5 R³ specially this one


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