Saved Bookmarks
| 1. |
The log - log graph between the energy `E` of an electron and its de - Broglie wavelength `lambda` will beA. B. C. D. |
|
Answer» Correct Answer - C As we know that, wavelength of a particle `lambda=h/(sqrt(2mE))=h/(sqrt(2m)).1/(sqrt(E)) rArr log lambda=log(h/(sqrt(2m)).1/sqrt(E))` `rArr log lambda = logh/sqrt(2m) + log 1/E^(1//2)` `rArr loglambda=log(h/sqrt(2m))-1/2logE` `rArr loglambda=-1/2logE+logh/sqrt(2m)` So, equation of straight line is y=mx +c This is equation of line with slope `-1/2` |
|