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The line `x+3y=0`is a diameter of the circle `x^2+y^2-6x+2y=0` |
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Answer» Correct Answer - 1 Since, centre of circle is (3, -1) which lies on x + 3y = 0 `rArr x + 3y = 0 " is diameter of " x^(2) + y^(2)-6x + 2y = 0` Hence, given statement is true. |
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