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The line that passes through the point (1, 4) and is perpendicular to the line 3x + 2y - 5 = 0 |
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Answer» Answer: LINE perpendicular to 3x+2y -5=0 is 2x-3y+k=0 it PASSES through (1,4) 2(1)-3(4)+k=0 2-7+k=0 k=5 hence required line is 2x-3y+5=0 hope it HELPS you please mark it as brainliest and follow me |
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