The line segment joining the mid - points of any two sides of a triangle is parallel to the third side and equal to half of it.In the given figure, the side AC of ΔABC is produced of E such that CE=12AC. If D is the mid - points of BC and ED produced meets AB at F and CP, DQ are drawn parallel to BA, then FD =

The line segment joining the mid - points of any two sides of a triang

1.	The line segment joining the mid - points of any two sides of a triangle is parallel to the third side and equal to half of it.In the given figure, the side AC of ΔABC is produced of E such that CE=12AC. If D is the mid - points of BC and ED produced meets AB at F and CP, DQ are drawn parallel to BA, then FD =
Answer» The line segment joining the mid - points of any two sides of a triangle is parallel to the third side and equal to half of it. In the given figure, the side AC of $Δ A B C$ is produced of E such that $C E = \frac{1}{2} A C$ . If D is the mid - points of BC and ED produced meets AB at F and CP, DQ are drawn parallel to BA, then FD =