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The line L1:x−41=y−21=z−k2 lies in the plane 2x−4y+z=7, then the equation of the plane containing the line L1 and perpendicular to the plane 2x−4y+z=7, is: |
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Answer» The line L1:x−41=y−21=z−k2 lies in the plane 2x−4y+z=7, then the equation of the plane containing the line L1 and perpendicular to the plane 2x−4y+z=7, is: |
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