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The level of water in a tank is 5 m high. A hole of area of cross section 1 `cm^(2)` is made at the bottom of the tank. The rate of leakage of water for the hole in `m^(3)s^(-1)` is `(g=10ms^(-2))`A. `10^(-3) m^(3)s^(-1)`B. `10^(-4) m^(3)s^(-1)`C. `10 m^(3)s^(-1)`D. `10^(-2) m^(3)s^(-1)` |
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Answer» Correct Answer - A Rate of leakage of water of from the hole `=Av=Asqrt(2gh)=10^(-4)sqrt(2xx10xx5)=10^(-3)m^(3)s^(-1)` |
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