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the length of wire of diameter 0.5 mm needed to produce a coil of resistance `10Omega` and specific resistance `4.4xx10^(-7)Omega` m isA. 4.45 mB. 5.55 mC. 5.45 mD. 1.45 m

Answer» Correct Answer - A
`R= (rho l)/(A)`
`:.l=(10xx3.14xx25xx10^(-8))/(4.4xx10^(-7)xx4)=(78.5)/(17.6)=4.45`m


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