The length of three sides of a triangle are in the ratio 3:4:5. If the

1.	The length of three sides of a triangle are in the ratio 3:4:5. If the perimeter of triangle is 192m, find area of triangle.
Answer» Answer: let SIDES of triangle of x 3x , 4x ,5x PERIMETER = 192m 3x+4x+5x= 192m 12x= 192m x= 192/12 x=16m a = 3x = 3×16 = 48m b= 4x = 4×16 = 64m c = 5x = 5×16 = 80m using heron's formula $\sqrt{s(s - a)(s - b)(s - c)}$ s= a+b+c/2 s= 96m $\sqrt{96(96 - 48)(96 - 64)(96 - 80)}$ $\sqrt{96 \times 48 \times 32 \times 16}$ 1536m ans

The length of three sides of a triangle are in the ratio 3:4:5. If the perimeter of triangle is 192m, find area of triangle.

Answer»

Answer:

let SIDES of triangle of x

3x , 4x ,5x

PERIMETER = 192m

3x+4x+5x= 192m

12x= 192m

x= 192/12

x=16m

a = 3x = 3×16 = 48m

b= 4x = 4×16 = 64m

c = 5x = 5×16 = 80m

using heron's formula

$\sqrt{s(s - a)(s - b)(s - c)}$

s= a+b+c/2

s= 96m

$\sqrt{96(96 - 48)(96 - 64)(96 - 80)}$

$\sqrt{96 \times 48 \times 32 \times 16}$

1536m ans

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The length of three sides of a triangle are in the ratio 3:4:5. If the perimeter of triangle is 192m, find area of triangle.

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